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(2-3v)=(2v-1)
We move all terms to the left:
(2-3v)-((2v-1))=0
We add all the numbers together, and all the variables
(-3v+2)-((2v-1))=0
We get rid of parentheses
-3v-((2v-1))+2=0
We calculate terms in parentheses: -((2v-1)), so:We get rid of parentheses
(2v-1)
We get rid of parentheses
2v-1
Back to the equation:
-(2v-1)
-3v-2v+1+2=0
We add all the numbers together, and all the variables
-5v+3=0
We move all terms containing v to the left, all other terms to the right
-5v=-3
v=-3/-5
v=3/5
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