(2-3x)(3-2x)=0

Solution for (2-3x)(3-2x)=0 equation:

(2-3x)(3-2x)=0

We add all the numbers together, and all the variables

(-3x+2)(-2x+3)=0

We multiply parentheses ..

(+6x^2-9x-4x+6)=0

We get rid of parentheses

6x^2-9x-4x+6=0

We add all the numbers together, and all the variables

6x^2-13x+6=0

a = 6; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·6·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*6}=\frac{8}{12}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*6}=\frac{18}{12}
=1+1/2
$