(2-3x)/4=(2x+2)/3

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Solution for (2-3x)/4=(2x+2)/3 equation: 



(2-3x)/4=(2x+2)/3

We move all terms to the left:

(2-3x)/4-((2x+2)/3)=0

We add all the numbers together, and all the variables

(-3x+2)/4-((2x+2)/3)=0

We calculate fractions


(-3x)/()+(-((2x+2)*4)/()=0



We calculate terms in parentheses: +(-((2x+2)*4)/(), so:

-((2x+2)*4)/(

We multiply all the terms by the denominator


-((2x+2)*4)



We calculate terms in parentheses: -((2x+2)*4), so:

(2x+2)*4

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

-8x-8

Back to the equation:

+(-8x-8)



We get rid of parentheses

(-3x)/()-8x-8=0

We multiply all the terms by the denominator


(-3x)-8x*()-8*()=0

We add all the numbers together, and all the variables

(-3x)-8x*()=0

We get rid of parentheses

-3x-8x*()=0

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