(2-3x)=15x2-22x+8

Solution for (2-3x)=15x2-22x+8 equation:

(2-3x)=15x^2-22x+8

We move all terms to the left:

(2-3x)-(15x^2-22x+8)=0

We add all the numbers together, and all the variables

(-3x+2)-(15x^2-22x+8)=0

We get rid of parentheses

-15x^2-3x+22x+2-8=0

We add all the numbers together, and all the variables

-15x^2+19x-6=0

a = -15; b = 19; c = -6;
Δ = b2-4ac
Δ = 192-4·(-15)·(-6)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-1}{2*-15}=\frac{-20}{-30}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+1}{2*-15}=\frac{-18}{-30}
=3/5
$