(2-4+x)=(x-5/8)

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Solution for (2-4+x)=(x-5/8) equation:



(2-4+x)=(x-5/8)
We move all terms to the left:
(2-4+x)-((x-5/8))=0
We add all the numbers together, and all the variables
(x-2)-((+x-5/8))=0
We get rid of parentheses
x-((+x-5/8))-2=0
We multiply all the terms by the denominator
x*8))-((+x-5-2*8))=0
We add all the numbers together, and all the variables
x*8))-((x-21))=0
We add all the numbers together, and all the variables
x*8))-((x=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$

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