(2-4x)-(3-4x)+4x=-(-3+6x)+x

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Solution for (2-4x)-(3-4x)+4x=-(-3+6x)+x equation: 



(2-4x)-(3-4x)+4x=-(-3+6x)+x

We move all terms to the left:

(2-4x)-(3-4x)+4x-(-(-3+6x)+x)=0

We add all the numbers together, and all the variables

(-4x+2)-(-4x+3)+4x-(-(6x-3)+x)=0

We add all the numbers together, and all the variables

4x+(-4x+2)-(-4x+3)-(-(6x-3)+x)=0

We get rid of parentheses

4x-4x+4x-(-(6x-3)+x)+2-3=0



We calculate terms in parentheses: -(-(6x-3)+x), so:

-(6x-3)+x

We add all the numbers together, and all the variables

x-(6x-3)

We get rid of parentheses

x-6x+3

We add all the numbers together, and all the variables

-5x+3

Back to the equation:

-(-5x+3)



We add all the numbers together, and all the variables

4x-(-5x+3)-1=0

We get rid of parentheses

4x+5x-3-1=0

We add all the numbers together, and all the variables

9x-4=0

We move all terms containing x to the left, all other terms to the right

9x=4

x=4/9

x=4/9

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