(2-5i)(p+q)i=29

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Solution for (2-5i)(p+q)i=29 equation:


Simplifying
(2 + -5i)(p + q) * i = 29

Reorder the terms for easier multiplication:
i(2 + -5i)(p + q) = 29

Multiply (2 + -5i) * (p + q)
i(2(p + q) + -5i * (p + q)) = 29
i((p * 2 + q * 2) + -5i * (p + q)) = 29
i((2p + 2q) + -5i * (p + q)) = 29
i(2p + 2q + (p * -5i + q * -5i)) = 29
i(2p + 2q + (-5ip + -5iq)) = 29

Reorder the terms:
i(-5ip + -5iq + 2p + 2q) = 29
i(-5ip + -5iq + 2p + 2q) = 29
(-5ip * i + -5iq * i + 2p * i + 2q * i) = 29

Reorder the terms:
(2ip + 2iq + -5i2p + -5i2q) = 29
(2ip + 2iq + -5i2p + -5i2q) = 29

Solving
2ip + 2iq + -5i2p + -5i2q = 29

Solving for variable 'i'.

Reorder the terms:
-29 + 2ip + 2iq + -5i2p + -5i2q = 29 + -29

Combine like terms: 29 + -29 = 0
-29 + 2ip + 2iq + -5i2p + -5i2q = 0

The solution to this equation could not be determined.

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