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(2-5i)*(1435i)=0

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Solution for (2-5i)*(1435i)=0 equation: 



(2-5i)(1435i)=0

We add all the numbers together, and all the variables

(-5i+2)1435i=0

We multiply parentheses

-7175i^2+2870i=0

a = -7175; b = 2870; c = 0;
Δ = b2-4ac
Δ = 28702-4·(-7175)·0
Δ = 8236900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
i_{1}=\frac{-b-\sqrt{\Delta}}{2a}
i_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{8236900}=2870


i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2870)-2870}{2*-7175}=\frac{-5740}{-14350}
=2/5



i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2870)+2870}{2*-7175}=\frac{0}{-14350}
=0

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