(2-5x)/3=(4-2x)/2

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Solution for (2-5x)/3=(4-2x)/2 equation: 



(2-5x)/3=(4-2x)/2

We move all terms to the left:

(2-5x)/3-((4-2x)/2)=0

We add all the numbers together, and all the variables

(-5x+2)/3-((-2x+4)/2)=0

We calculate fractions


(-5x)/()+(-((-2x+4)*3)/()=0



We calculate terms in parentheses: +(-((-2x+4)*3)/(), so:

-((-2x+4)*3)/(

We multiply all the terms by the denominator


-((-2x+4)*3)



We calculate terms in parentheses: -((-2x+4)*3), so:

(-2x+4)*3

We multiply parentheses

-6x+12

Back to the equation:

-(-6x+12)



We get rid of parentheses

6x-12

Back to the equation:

+(6x-12)



We get rid of parentheses

(-5x)/()+6x-12=0

We multiply all the terms by the denominator


(-5x)+6x*()-12*()=0

We add all the numbers together, and all the variables

(-5x)+6x*()=0

We get rid of parentheses

-5x+6x*()=0

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