(2-i)(2+i)=

Solution for (2-i)(2+i)= equation:

Simplifying
(2 + -1i)(2 + i) = 0

Multiply (2 + -1i) * (2 + i)
(2(2 + i) + -1i * (2 + i)) = 0
((2 * 2 + i * 2) + -1i * (2 + i)) = 0
((4 + 2i) + -1i * (2 + i)) = 0
(4 + 2i + (2 * -1i + i * -1i)) = 0
(4 + 2i + (-2i + -1i2)) = 0

Combine like terms: 2i + -2i = 0
(4 + 0 + -1i2) = 0
(4 + -1i2) = 0

Solving
4 + -1i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1i2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1i2 = 0 + -4
-1i2 = 0 + -4

Combine like terms: 0 + -4 = -4
-1i2 = -4

Divide each side by '-1'.
i2 = 4

Simplifying
i2 = 4

Take the square root of each side:
i = {-2, 2}