(2-i)*z-4=0

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Solution for (2-i)*z-4=0 equation:


Simplifying
(2 + -1i) * z + -4 = 0

Reorder the terms for easier multiplication:
z(2 + -1i) + -4 = 0
(2 * z + -1i * z) + -4 = 0

Reorder the terms:
(-1iz + 2z) + -4 = 0
(-1iz + 2z) + -4 = 0

Reorder the terms:
-4 + -1iz + 2z = 0

Solving
-4 + -1iz + 2z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + -1iz + 4 + 2z = 0 + 4

Reorder the terms:
-4 + 4 + -1iz + 2z = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1iz + 2z = 0 + 4
-1iz + 2z = 0 + 4

Combine like terms: 0 + 4 = 4
-1iz + 2z = 4

Add '-2z' to each side of the equation.
-1iz + 2z + -2z = 4 + -2z

Combine like terms: 2z + -2z = 0
-1iz + 0 = 4 + -2z
-1iz = 4 + -2z

Divide each side by '-1z'.
i = -4z-1 + 2

Simplifying
i = -4z-1 + 2

Reorder the terms:
i = 2 + -4z-1

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