(2-i)z-2i=3i+2-3i

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Solution for (2-i)z-2i=3i+2-3i equation:


Simplifying
(2 + -1i) * z + -2i = 3i + 2 + -3i

Reorder the terms for easier multiplication:
z(2 + -1i) + -2i = 3i + 2 + -3i
(2 * z + -1i * z) + -2i = 3i + 2 + -3i

Reorder the terms:
(-1iz + 2z) + -2i = 3i + 2 + -3i
(-1iz + 2z) + -2i = 3i + 2 + -3i

Reorder the terms:
-2i + -1iz + 2z = 3i + 2 + -3i

Reorder the terms:
-2i + -1iz + 2z = 2 + 3i + -3i

Combine like terms: 3i + -3i = 0
-2i + -1iz + 2z = 2 + 0
-2i + -1iz + 2z = 2

Solving
-2i + -1iz + 2z = 2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-2i + -1iz + 2z + -2z = 2 + -2z

Combine like terms: 2z + -2z = 0
-2i + -1iz + 0 = 2 + -2z
-2i + -1iz = 2 + -2z

Reorder the terms:
-2 + -2i + -1iz + 2z = 2 + -2z + -2 + 2z

Reorder the terms:
-2 + -2i + -1iz + 2z = 2 + -2 + -2z + 2z

Combine like terms: 2 + -2 = 0
-2 + -2i + -1iz + 2z = 0 + -2z + 2z
-2 + -2i + -1iz + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
-2 + -2i + -1iz + 2z = 0

The solution to this equation could not be determined.

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