(2-j)(3+j)=

Solution for (2-j)(3+j)= equation:

Simplifying
(2 + -1j)(3 + j) = 0

Multiply (2 + -1j) * (3 + j)
(2(3 + j) + -1j * (3 + j)) = 0
((3 * 2 + j * 2) + -1j * (3 + j)) = 0
((6 + 2j) + -1j * (3 + j)) = 0
(6 + 2j + (3 * -1j + j * -1j)) = 0
(6 + 2j + (-3j + -1j2)) = 0

Combine like terms: 2j + -3j = -1j
(6 + -1j + -1j2) = 0

Solving
6 + -1j + -1j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(2 + -1j)(3 + j) = 0

Subproblem 1
Set the factor '(2 + -1j)' equal to zero and attempt to solve:

Simplifying
2 + -1j = 0

Solving
2 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1j = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1j = 0 + -2
-1j = 0 + -2

Combine like terms: 0 + -2 = -2
-1j = -2

Divide each side by '-1'.
j = 2

Simplifying
j = 2
Subproblem 2
Set the factor '(3 + j)' equal to zero and attempt to solve:

Simplifying
3 + j = 0

Solving
3 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + j = 0 + -3
j = 0 + -3

Combine like terms: 0 + -3 = -3
j = -3

Simplifying
j = -3
Solution
j = {2, -3}