(2-s)/3=(2s+1)/5

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Solution for (2-s)/3=(2s+1)/5 equation:



(2-s)/3=(2s+1)/5
We move all terms to the left:
(2-s)/3-((2s+1)/5)=0
We add all the numbers together, and all the variables
(-1s+2)/3-((2s+1)/5)=0
We calculate fractions
(-s)/()+(-((2s+1)*3)/()=0
We calculate terms in parentheses: +(-((2s+1)*3)/(), so:
-((2s+1)*3)/(
We multiply all the terms by the denominator
-((2s+1)*3)
We calculate terms in parentheses: -((2s+1)*3), so:
(2s+1)*3
We multiply parentheses
6s+3
Back to the equation:
-(6s+3)
We get rid of parentheses
-6s-3
Back to the equation:
+(-6s-3)
We add all the numbers together, and all the variables
(-1s)/()+(-6s-3)=0
We get rid of parentheses
(-1s)/()-6s-3=0
We multiply all the terms by the denominator
(-1s)-6s*()-3*()=0
We add all the numbers together, and all the variables
(-1s)-6s*()=0
We get rid of parentheses
-1s-6s*()=0

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