(2-u)(5u-6)=0

Solution for (2-u)(5u-6)=0 equation:

(2-u)(5u-6)=0

We add all the numbers together, and all the variables

(-1u+2)(5u-6)=0

We multiply parentheses ..

(-5u^2+6u+10u-12)=0

We get rid of parentheses

-5u^2+6u+10u-12=0

We add all the numbers together, and all the variables

-5u^2+16u-12=0

a = -5; b = 16; c = -12;
Δ = b2-4ac
Δ = 162-4·(-5)·(-12)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*-5}=\frac{-20}{-10}
=+2
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*-5}=\frac{-12}{-10}
=1+1/5
$