(2-v)(5v+8)=0

Solution for (2-v)(5v+8)=0 equation:

(2-v)(5v+8)=0

We add all the numbers together, and all the variables

(-1v+2)(5v+8)=0

We multiply parentheses ..

(-5v^2-8v+10v+16)=0

We get rid of parentheses

-5v^2-8v+10v+16=0

We add all the numbers together, and all the variables

-5v^2+2v+16=0

a = -5; b = 2; c = +16;
Δ = b2-4ac
Δ = 22-4·(-5)·16
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-18}{2*-5}=\frac{-20}{-10}
=+2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+18}{2*-5}=\frac{16}{-10}
=-1+3/5
$