(2-x)(8-x)+24=40

Solution for (2-x)(8-x)+24=40 equation:

(2-x)(8-x)+24=40

We move all terms to the left:

(2-x)(8-x)+24-(40)=0

We add all the numbers together, and all the variables

(-1x+2)(-1x+8)+24-40=0

We add all the numbers together, and all the variables

(-1x+2)(-1x+8)-16=0

We multiply parentheses ..

(+x^2-8x-2x+16)-16=0

We get rid of parentheses

x^2-8x-2x+16-16=0

We add all the numbers together, and all the variables

x^2-10x=0

a = 1; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·1·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*1}=\frac{20}{2}
=10
$