(2-x)/(x+2)+3=4/(x+2)

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Solution for (2-x)/(x+2)+3=4/(x+2) equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

(2-x)/(x+2)+3 = 4/(x+2) // - 4/(x+2)

(2-x)/(x+2)-(4/(x+2))+3 = 0

(2-x)/(x+2)-4*(x+2)^-1+3 = 0

(2-x)/(x+2)-4/(x+2)+3 = 0

(2-x)/(x+2)-4/(x+2)+(3*(x+2))/(x+2) = 0

3*(x+2)-x-4+2 = 0

3*x-x-2+6 = 0

2*x+4 = 0

(2*x+4)/(x+2) = 0

(2*x+4)/(x+2) = 0 // * x+2

2*x+4 = 0

2*x+4 = 0 // - 4

2*x = -4 // : 2

x = -4/2

x = -2

x in { -2} 

x belongs to the empty set

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