(2-x)/3(3-2x)/5

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Solution for (2-x)/3(3-2x)/5 equation: 


x in (-oo:+oo)

(2-x)/3 < (3-(2*x))/5 // - (3-(2*x))/5

(2-x)/3-((3-(2*x))/5) < 0

(2-x)/3-((3-2*x)/5) < 0

(2-x)/3+(-1*(3-2*x))/5 < 0

(5*(2-x))/(3*5)+(-1*3*(3-2*x))/(3*5) < 0

5*(2-x)-1*3*(3-2*x) < 0

x+1 < 0

(x+1)/(3*5) < 0

(x+1)/(3*5) < 0 // * (3*5)^2

3*5*(x+1) < 0

( 3 )

3 < 0

x belongs to the empty set

( 5 )

5 < 0

x belongs to the empty set

( x+1 )

x+1 < 0 // - 1

x < -1

	(-oo:-1)	(-1:+oo)
3	+	+
5	+	+
x+1	-	+


x in (-oo:-1)

(-oo:-1)

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