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(2-x)/3=x-2
We move all terms to the left:
(2-x)/3-(x-2)=0
We add all the numbers together, and all the variables
(-1x+2)/3-(x-2)=0
We get rid of parentheses
(-1x+2)/3-x+2=0
We multiply all the terms by the denominator
(-1x+2)-x*3+2*3=0
We add all the numbers together, and all the variables
(-1x+2)-x*3+6=0
Wy multiply elements
(-1x+2)-3x+6=0
We get rid of parentheses
-1x-3x+2+6=0
We add all the numbers together, and all the variables
-4x+8=0
We move all terms containing x to the left, all other terms to the right
-4x=-8
x=-8/-4
x=+2
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