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(2-x)3x=6x
We move all terms to the left:
(2-x)3x-(6x)=0
We add all the numbers together, and all the variables
(-1x+2)3x-6x=0
We add all the numbers together, and all the variables
-6x+(-1x+2)3x=0
We multiply parentheses
-3x^2-6x+6x=0
We add all the numbers together, and all the variables
-3x^2=0
a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-6}=0$
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