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(2-y)(5y-4)=0
We add all the numbers together, and all the variables
(-1y+2)(5y-4)=0
We multiply parentheses ..
(-5y^2+4y+10y-8)=0
We get rid of parentheses
-5y^2+4y+10y-8=0
We add all the numbers together, and all the variables
-5y^2+14y-8=0
a = -5; b = 14; c = -8;
Δ = b2-4ac
Δ = 142-4·(-5)·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6}{2*-5}=\frac{-20}{-10} =+2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6}{2*-5}=\frac{-8}{-10} =4/5 $
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