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(2-z)(5z-1)=0
We add all the numbers together, and all the variables
(-1z+2)(5z-1)=0
We multiply parentheses ..
(-5z^2+z+10z-2)=0
We get rid of parentheses
-5z^2+z+10z-2=0
We add all the numbers together, and all the variables
-5z^2+11z-2=0
a = -5; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·(-5)·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-9}{2*-5}=\frac{-20}{-10} =+2 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+9}{2*-5}=\frac{-2}{-10} =1/5 $
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