(2/(3x))+(3/5)=(9/(10x))

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Solution for (2/(3x))+(3/5)=(9/(10x)) equation: 


D( x )

10*x = 0

3*x = 0

10*x = 0

10*x = 0

10*x = 0 // : 10

x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

2/(3*x)+3/5 = 9/(10*x) // - 9/(10*x)

2/(3*x)-(9/(10*x))+3/5 = 0

2/(3*x)+(-9/10)*x^-1+3/5 = 0

-7/30*x^-1 = -3/5 // : -7/30

x^-1 = 18/7

-1 < 0

1/(x^1) = 18/7 // * x^1

1 = 18/7*x^1 // : 18/7

7/18 = x^1

x = 7/18

x = 7/18

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