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(2/(3x-1))+(3/(3x+1))=5/(3x)
We move all terms to the left:
(2/(3x-1))+(3/(3x+1))-(5/(3x))=0
Domain of the equation: (3x-1))!=0
x∈R
Domain of the equation: (3x+1))!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(2/(3x-1))+(3/(3x+1))-(+5/3x)=0
We get rid of parentheses
(2/(3x-1))+(3/(3x+1))-5/3x=0
We calculate fractions
((2*(3x+1))*3x)/((3x-1))*(3x+1))*3x)+((3*(3x-1))*3x)/((3x-1))*(3x+1))*3x)+(-5*(3x-1))*3x/((3x-1))*(3x+1))*3x)=0
We can not solve this equation
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