If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( t )
4-t = 0
t-4 = 0
t = 0
4-t = 0
4-t = 0
4-t = 0 // - 4
-t = -4 // * -1
t = 4
t-4 = 0
t-4 = 0
t-4 = 0 // + 4
t = 4
t = 0
t = 0
t in (-oo:0) U (0:4) U (4:+oo)
2/(t-4)+1/t = t/(4-t) // - t/(4-t)
2/(t-4)-(t/(4-t))+1/t = 0
2/(t-4)+(-1*t)/(4-t)+1/t = 0
(2*t*(4-t))/(t*(t-4)*(4-t))+(-1*t^2*(t-4))/(t*(t-4)*(4-t))+(1*(t-4)*(4-t))/(t*(t-4)*(4-t)) = 0
2*t*(4-t)-1*t^2*(t-4)+1*(t-4)*(4-t) = 0
2*t^2-t^3-t^2+8*t+8*t-16 = 0
t^2-t^3+16*t-16 = 0
t^2-t^3+16*t-16 = 0
t^2-t^3+16*t-16 = 0
{ 1, -1, 2, -2, 4, -4, 8, -8, 16, -16 }
1
t = 1
t^2-t^3+16*t-16 = 0
1
t-1
16-t^2
t^2-t^3+16*t-16
t-1
t^3-t^2
16*t-16
16-16*t
0
16-t^2 = 0
DELTA = 0^2-(-1*4*16)
DELTA = 64
DELTA > 0
t = (64^(1/2)+0)/(-1*2) or t = (0-64^(1/2))/(-1*2)
t = -4 or t = 4
t in { -4, 4, 1}
(t+4)*(t-4)*(t-1) = 0
((t+4)*(t-4)*(t-1))/(t*(t-4)*(4-t)) = 0
((t+4)*(t-4)*(t-1))/(t*(t-4)*(4-t)) = 0 // * t*(t-4)*(4-t)
(t+4)*(t-4)*(t-1) = 0
( t+4 )
t+4 = 0 // - 4
t = -4
( t-1 )
t-1 = 0 // + 1
t = 1
( t-4 )
t-4 = 0 // + 4
t = 4
t in { 4}
t in { -4, 1 }
| (2/(3x))+(3/5)=(9/(10x)) | | (2.550*340)/(192+340)=x | | t^2-8t-3=0 | | (2.04+6r)/4=7 | | 7-12x-4x^2= | | (2-x)/8=(x+6)/3 | | (2-x)/(4+2x)=8 | | (2-x)/(3-2x)=0 | | (2-x)/(1+x)=1 | | (2-7x)/3=5(x-4)/9 | | (2-5y)/(3y-1)=6 | | (2-4y)2/9=4 | | -9(3)+15=x | | (2-4x)/(7x)=(5)/(2) | | (2-(4/(x+2)))/(5+(10/(x+2)))=0 | | (2,6)m=5/4 | | (2+x)/6=(3-x)/3 | | (2+t/6)-3t=4+(t-5/6) | | (2+k)/7=-2 | | (2+c)/9=18/27 | | 7+-3=4n | | (2+3i)x+(4-2i)=(8+4i)/(1-i) | | (2+3i)/(4-2i)=0 | | (2+3)5=50/y | | (2*x)/3=4 | | (2*3.14)/(-1/3)=0 | | (2)6/31x=x | | (2)1/7p=-3 | | (2)/(y-2)-3y=(4y-1)/(y-2) | | (2)/(j+3)=(4)/(5) | | (2)/(5x+1)=(1)/(2x-1) | | (2)/(5)X+10=0 |