(2/(x+2))+(3/(x-1))=-(8/5)

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Solution for (2/(x+2))+(3/(x-1))=-(8/5) equation: 


D( x )

x+2 = 0

x-1 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-2) U (-2:1) U (1:+oo)

2/(x+2)+3/(x-1) = -(8/5) // + 8/5

2/(x+2)+3/(x-1)+8/5 = 0

(2*5*(x-1))/(5*(x+2)*(x-1))+(3*5*(x+2))/(5*(x+2)*(x-1))+(8*(x+2)*(x-1))/(5*(x+2)*(x-1)) = 0

2*5*(x-1)+3*5*(x+2)+8*(x+2)*(x-1) = 0

8*x^2+25*x+8*x-16+20 = 0

8*x^2+33*x+4 = 0

8*x^2+33*x+4 = 0

8*x^2+33*x+4 = 0

DELTA = 33^2-(4*4*8)

DELTA = 961

DELTA > 0

x = (961^(1/2)-33)/(2*8) or x = (-961^(1/2)-33)/(2*8)

x = -1/8 or x = -4

(x+4)*(x+1/8) = 0

((x+4)*(x+1/8))/(5*(x+2)*(x-1)) = 0

((x+4)*(x+1/8))/(5*(x+2)*(x-1)) = 0 // * 5*(x+2)*(x-1)

(x+4)*(x+1/8) = 0

( x+1/8 )

x+1/8 = 0 // - 1/8

x = -1/8

( x+4 )

x+4 = 0 // - 4

x = -4

x in { -1/8, -4 }

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