(2/(x+3))+(3/x)=(1/2)

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Solution for (2/(x+3))+(3/x)=(1/2) equation:


D( x )

x = 0

x+3 = 0

x = 0

x = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:0) U (0:+oo)

2/(x+3)+3/x = 1/2 // - 1/2

2/(x+3)+3/x-(1/2) = 0

2/(x+3)+3/x-1/2 = 0

(2^2*x)/(2*x*(x+3))+(2*3*(x+3))/(2*x*(x+3))+(-1*x*(x+3))/(2*x*(x+3)) = 0

2*3*(x+3)-1*x*(x+3)+2^2*x = 0

10*x-x^2-3*x+18 = 0

7*x-x^2+18 = 0

7*x-x^2+18 = 0

7*x-x^2+18 = 0

DELTA = 7^2-(-1*4*18)

DELTA = 121

DELTA > 0

x = (121^(1/2)-7)/(-1*2) or x = (-121^(1/2)-7)/(-1*2)

x = -2 or x = 9

(x+2)*(x-9) = 0

((x+2)*(x-9))/(2*x*(x+3)) = 0

((x+2)*(x-9))/(2*x*(x+3)) = 0 // * 2*x*(x+3)

(x+2)*(x-9) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-9 )

x-9 = 0 // + 9

x = 9

x in { -2, 9 }

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