(2/(x-1))+2=(8/(x-1))

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Solution for (2/(x-1))+2=(8/(x-1)) equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

2/(x-1)+2 = 8/(x-1) // - 8/(x-1)

2/(x-1)-(8/(x-1))+2 = 0

2/(x-1)-8*(x-1)^-1+2 = 0

2/(x-1)-8/(x-1)+2 = 0

2/(x-1)-8/(x-1)+(2*(x-1))/(x-1) = 0

2*(x-1)-8+2 = 0

2*x-6-2 = 0

2*x-8 = 0

(2*x-8)/(x-1) = 0

(2*x-8)/(x-1) = 0 // * x-1

2*x-8 = 0

2*x-8 = 0 // + 8

2*x = 8 // : 2

x = 8/2

x = 4

x = 4

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