(2/11)m+16=4+(6/11)m

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Solution for (2/11)m+16=4+(6/11)m equation:



(2/11)m+16=4+(6/11)m
We move all terms to the left:
(2/11)m+16-(4+(6/11)m)=0
Domain of the equation: 11)m!=0
m!=0/1
m!=0
m∈R
Domain of the equation: 11)m)!=0
m!=0/1
m!=0
m∈R
We add all the numbers together, and all the variables
(+2/11)m-(4+(+6/11)m)+16=0
We multiply parentheses
2m^2-(4+(+6/11)m)+16=0
We multiply all the terms by the denominator
2m^2*11)m)-(4+(+16*11)m)+6=0
We add all the numbers together, and all the variables
2m^2*11)m)-(4+176m)+6=0
Wy multiply elements
22m^3=0
We do not support empression: m^3

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