(2/3)(15-4y)=(5/6)(3y+12)

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Solution for (2/3)(15-4y)=(5/6)(3y+12) equation: 


y in (-oo:+oo)

(2/3)*(15-(4*y)) = (5/6)*(3*y+12) // - (5/6)*(3*y+12)

(2/3)*(15-(4*y))-((5/6)*(3*y+12)) = 0

(2/3)*(15-4*y)+(-5/6)*(3*y+12) = 0

2/3*(15-4*y)-5/6*(3*y+12) = 0

2/3*(15-4*y)-5/6*(3*y+12) = 0

-31/6*y = 0

(-31*y)/6 = 0

(-31*y)/6 = 0 // * 6

-31*y = 0

-31*y = 0 // : -31

y = 0

y = 0

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