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(2/3)(3-9x)=-10-(1/2)(6x+4)
We move all terms to the left:
(2/3)(3-9x)-(-10-(1/2)(6x+4))=0
Domain of the equation: 3)(3-9x)!=0
x∈R
Domain of the equation: 2)(6x+4))!=0We add all the numbers together, and all the variables
x∈R
(+2/3)(-9x+3)-(-10-(+1/2)(6x+4))=0
We multiply parentheses ..
(-18x^2+2/3*3)-(-10-(+1/2)(6x+4))=0
We calculate fractions
((-18x^2+2*2)(6x+4)))/18x^2+()/18x^2=0
We can not solve this equation
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