(2/3)(6c-18)+(3/4)(8c+32)=18

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Solution for (2/3)(6c-18)+(3/4)(8c+32)=18 equation: 



(2/3)(6c-18)+(3/4)(8c+32)=18

We move all terms to the left:

(2/3)(6c-18)+(3/4)(8c+32)-(18)=0



Domain of the equation: 3)(6c-18)!=0

c∈R





Domain of the equation: 4)(8c+32)!=0

c∈R



We add all the numbers together, and all the variables

(+2/3)(6c-18)+(+3/4)(8c+32)-18=0

We multiply parentheses ..

(+12c^2+2/3*-18)+(+3/4)(8c+32)-18=0

We calculate fractions

There is no solution for this equation

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