(2/3)(6x+30)=x+5(x+4)-2x

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Solution for (2/3)(6x+30)=x+5(x+4)-2x equation: 


x in (-oo:+oo)

(2/3)*(6*x+30) = 5*(x+4)+x-(2*x) // - 5*(x+4)+x-(2*x)

(2/3)*(6*x+30)-(5*(x+4))-x+2*x = 0

(2/3)*(6*x+30)-5*(x+4)-x+2*x = 0

2/3*(6*x+30)-5*(x+4)-x+2*x = 0

2/3*(6*x+30)-5*(x+4)-x+2*x = 0

2*x-x-x = 0

2*x-2*x = 0

0 = 0

0 = 0

x belongs to the empty set

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