(2/3)(6x-18)+(3/4)(8x+32)=-18

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Solution for (2/3)(6x-18)+(3/4)(8x+32)=-18 equation:



(2/3)(6x-18)+(3/4)(8x+32)=-18
We move all terms to the left:
(2/3)(6x-18)+(3/4)(8x+32)-(-18)=0
Domain of the equation: 3)(6x-18)!=0
x∈R
Domain of the equation: 4)(8x+32)!=0
x∈R
We add all the numbers together, and all the variables
(+2/3)(6x-18)+(+3/4)(8x+32)-(-18)=0
We add all the numbers together, and all the variables
(+2/3)(6x-18)+(+3/4)(8x+32)+18=0
We multiply parentheses ..
(+12x^2+2/3*-18)+(+3/4)(8x+32)+18=0
We calculate fractions
There is no solution for this equation

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