(2/3)(6x-5)=2-(1/3)(3x-2)

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Solution for (2/3)(6x-5)=2-(1/3)(3x-2) equation:



(2/3)(6x-5)=2-(1/3)(3x-2)
We move all terms to the left:
(2/3)(6x-5)-(2-(1/3)(3x-2))=0
Domain of the equation: 3)(6x-5)!=0
x∈R
Domain of the equation: 3)(3x-2))!=0
x∈R
We add all the numbers together, and all the variables
(+2/3)(6x-5)-(2-(+1/3)(3x-2))=0
We multiply parentheses ..
(+12x^2+2/3*-5)-(2-(+1/3)(3x-2))=0
We calculate fractions
((+12x^2+2*3)(3x-2)))/(-5)*3)(3x-2))+3*)+()/(-5)*3)(3x-2))+3*)=0
We calculate fractions
(((+12x^2+2*3)(3x-2)))*(-5)*3)(3x-2))+3*))/((*(-5)*3)3x)+(-5)*3)(3x-2))+3*)+()*()/((*(-5)*3)3x)=0
We can not solve this equation

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