(2/3)(6x-9)=-12

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Solution for (2/3)(6x-9)=-12 equation: 



(2/3)(6x-9)=-12

We move all terms to the left:

(2/3)(6x-9)-(-12)=0



Domain of the equation: 3)(6x-9)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(6x-9)-(-12)=0

We add all the numbers together, and all the variables

(+2/3)(6x-9)+12=0

We multiply parentheses ..

(+12x^2+2/3*-9)+12=0

We multiply all the terms by the denominator


(+12x^2+2+12*3*-9)=0

We get rid of parentheses

12x^2+2-9+12*3*=0

We add all the numbers together, and all the variables

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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