(2/3)(x+0.5)=-1

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Solution for (2/3)(x+0.5)=-1 equation:



(2/3)(x+0.5)=-1
We move all terms to the left:
(2/3)(x+0.5)-(-1)=0
Domain of the equation: 3)(x+0.5)!=0
x∈R
We add all the numbers together, and all the variables
(+2/3)(x+0.5)-(-1)=0
We add all the numbers together, and all the variables
(+2/3)(x+0.5)+1=0
We multiply parentheses ..
(+2x^2+2/3*0.5)+1=0
We multiply all the terms by the denominator
(+2x^2+2+1*3*0.5)=0
We get rid of parentheses
2x^2+2+1*3*0.5=0
We add all the numbers together, and all the variables
2x^2+3.5=0
a = 2; b = 0; c = +3.5;
Δ = b2-4ac
Δ = 02-4·2·3.5
Δ = -28
Delta is less than zero, so there is no solution for the equation

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