(2/3)(x-11)=4+x

Solution for (2/3)(x-11)=4+x equation:

(2/3)(x-11)=4+x

We move all terms to the left:

(2/3)(x-11)-(4+x)=0


Domain of the equation: 3)(x-11)!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)(x-11)-(x+4)=0

We get rid of parentheses

(+2/3)(x-11)-x-4=0

We multiply parentheses ..

(+2x^2+2/3*-11)-x-4=0

We multiply all the terms by the denominator


(+2x^2+2-x*3*-11)-4*3*-11)=0

We add all the numbers together, and all the variables

(+2x^2+2-x*3*-11)=0

We get rid of parentheses

2x^2-x*3*+2-11=0

We add all the numbers together, and all the variables

2x^2-x*3*-9=0

Wy multiply elements

2x^2-3x^2-9=0

We add all the numbers together, and all the variables

-1x^2-9=0

a = -1; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·(-1)·(-9)
Δ = -36
Delta is less than zero, so there is no solution for the equation