(2/3)(x-4)(x+5)=1

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Solution for (2/3)(x-4)(x+5)=1 equation: 



(2/3)(x-4)(x+5)=1

We move all terms to the left:

(2/3)(x-4)(x+5)-(1)=0



Domain of the equation: 3)(x-4)(x+5)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(x-4)(x+5)-1=0

We multiply parentheses ..

(+2x^2+2/3*-4)(x+5)-1=0

We multiply all the terms by the denominator


(+2x^2+2-1*3*-4)(x+5)=0

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