(2/3)(x-6)+1=x-2

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Solution for (2/3)(x-6)+1=x-2 equation: 



(2/3)(x-6)+1=x-2

We move all terms to the left:

(2/3)(x-6)+1-(x-2)=0



Domain of the equation: 3)(x-6)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(x-6)-(x-2)+1=0

We get rid of parentheses

(+2/3)(x-6)-x+2+1=0

We multiply parentheses ..

(+2x^2+2/3*-6)-x+2+1=0

We multiply all the terms by the denominator


(+2x^2+2-x*3*-6)+2*3*-6)+1*3*-6)=0

We add all the numbers together, and all the variables

(+2x^2+2-x*3*-6)=0

We get rid of parentheses

2x^2-x*3*+2-6=0

We add all the numbers together, and all the variables

2x^2-x*3*-4=0

Wy multiply elements

2x^2-3x^2-4=0

We add all the numbers together, and all the variables

-1x^2-4=0

a = -1; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-1)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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