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(2/3)(x-9)=2/3x-6
We move all terms to the left:
(2/3)(x-9)-(2/3x-6)=0
Domain of the equation: 3)(x-9)!=0
x∈R
Domain of the equation: 3x-6)!=0We add all the numbers together, and all the variables
x∈R
(+2/3)(x-9)-(2/3x-6)=0
We get rid of parentheses
(+2/3)(x-9)-2/3x+6=0
We multiply parentheses ..
(+2x^2+2/3*-9)-2/3x+6=0
We calculate fractions
((+2x^2+2*3x)/(-9)*3x+3*)+()/(-9)*3x+6+3*)=0
We calculate terms in parentheses: +((+2x^2+2*3x)/(-9)*3x+3*), so:We add all the numbers together, and all the variables
(+2x^2+2*3x)/(-9)*3x+3*
We add all the numbers together, and all the variables
(+2x^2+2*3x)/(-9)*3x
We multiply all the terms by the denominator
(+2x^2+2*3x)
We get rid of parentheses
2x^2+2*3x
Wy multiply elements
2x^2+6x
Back to the equation:
+(2x^2+6x)
(2x^2+6x)+()/(-9)*3x=0
We get rid of parentheses
2x^2+6x+()/(-9)*3x=0
We multiply all the terms by the denominator
2x^2*(-9)*3x+6x*(-9)*3x+()=0
We add all the numbers together, and all the variables
2x^2*(-9)*3x+6x*(-9)*3x=0
We multiply parentheses
2x^2*(-9)*3x-162x^2=0
We add all the numbers together, and all the variables
-162x^2+2x^2*(-9)*3x=0
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