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(2/3)*25x+(1/3)*12x-15x=1700
We move all terms to the left:
(2/3)*25x+(1/3)*12x-15x-(1700)=0
Domain of the equation: 3)*25x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3)*12x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)*25x+(+1/3)*12x-15x-1700=0
We add all the numbers together, and all the variables
-15x+(+2/3)*25x+(+1/3)*12x-1700=0
We multiply parentheses
50x^2+12x^2-15x-1700=0
We add all the numbers together, and all the variables
62x^2-15x-1700=0
a = 62; b = -15; c = -1700;
Δ = b2-4ac
Δ = -152-4·62·(-1700)
Δ = 421825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{421825}=\sqrt{25*16873}=\sqrt{25}*\sqrt{16873}=5\sqrt{16873}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5\sqrt{16873}}{2*62}=\frac{15-5\sqrt{16873}}{124} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5\sqrt{16873}}{2*62}=\frac{15+5\sqrt{16873}}{124} $
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