(2/3)*a+2=(1/3)*(4a+1)

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Solution for (2/3)*a+2=(1/3)*(4a+1) equation: 



(2/3)*a+2=(1/3)(4a+1)

We move all terms to the left:

(2/3)*a+2-((1/3)(4a+1))=0



Domain of the equation: 3)*a!=0

a!=0/1

a!=0

a∈R





Domain of the equation: 3)(4a+1))!=0

a∈R



We add all the numbers together, and all the variables

(+2/3)*a-((+1/3)(4a+1))+2=0

We multiply parentheses

2a^2-((+1/3)(4a+1))+2=0

We multiply parentheses ..

2a^2-((+4a^2+1/3*1))+2=0

We multiply all the terms by the denominator


4a^2+2a^2*3*1))-((+1+2*3*1))=0

We add all the numbers together, and all the variables

4a^2+2a^2*3*1))-(7)=0

We add all the numbers together, and all the variables

4a^2+2a^2*3*1))-7=0

Wy multiply elements

4a^2+6a^3*1=0

We do not support eapression: a^3

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