(2/3)*x+4=(1/6)*x-3

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Solution for (2/3)*x+4=(1/6)*x-3 equation: 



(2/3)*x+4=(1/6)*x-3

We move all terms to the left:

(2/3)*x+4-((1/6)*x-3)=0



Domain of the equation: 3)*x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 6)*x-3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)*x-((+1/6)*x-3)+4=0

We multiply parentheses

2x^2-((+1/6)*x-3)+4=0

We multiply all the terms by the denominator


2x^2*6)*x-3)-((+4*6)*x-3)+1=0

We add all the numbers together, and all the variables

2x^2*6)*x-3)-(24*x-3)+1=0

Wy multiply elements

12x^5=0

We do not support expression: x^5

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