If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2/3)*x=120
We move all terms to the left:
(2/3)*x-(120)=0
Domain of the equation: 3)*x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)*x-120=0
We multiply parentheses
2x^2-120=0
a = 2; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·2·(-120)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{15}}{2*2}=\frac{0-8\sqrt{15}}{4} =-\frac{8\sqrt{15}}{4} =-2\sqrt{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{15}}{2*2}=\frac{0+8\sqrt{15}}{4} =\frac{8\sqrt{15}}{4} =2\sqrt{15} $
| a(12)=132 | | (12x-25)=(x-3) | | (x-3)=(12x-25) | | x(9)=117 | | 5x-20=-x+4 | | 59=83+8x | | (x^2+3)^2=4x^2+12 | | 2/3x-4(x+8)=3-10x | | ½x+x=4-2 | | 53x=25(x+2) | | 9^y=34 | | 3^2y=64 | | 01b*5=10b-6 | | ½x+x=-2 | | 3/5=1.75/x | | .7(3x–2)=3.5x+1 | | 10*8x=50*3x | | 4x(2x+3)=5-x | | 2x²+10=60 | | 77=x+35 | | X/5+x/1=11/30 | | 2x+55=x+100 | | 10x=1220 | | 4.9x^2+4x-750=0 | | 1/2x+5/24=1/3x-1/8 | | 4b-12=14b | | n÷11=3 | | 1=10x+42=5x-4 | | n|11=3 | | 16t^2+24t+50=0 | | 3x-8=x5 | | x=900+1.5x |