(2/3)+(1/5)=(1/x)

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Solution for (2/3)+(1/5)=(1/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/3+1/5 = 1/x // - 1/x

2/3-(1/x)+1/5 = 0

2/3-x^-1+1/5 = 0

-1*x^-1 = -13/15 // : -1

x^-1 = 13/15

-1 < 0

1/(x^1) = 13/15 // * x^1

1 = 13/15*x^1 // : 13/15

15/13 = x^1

x = 15/13

x = 15/13

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