(2/3)+(3k/4)=(71/12)

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Solution for (2/3)+(3k/4)=(71/12) equation: 


k in (-oo:+oo)

(3*k)/4+2/3 = 71/12 // - 71/12

(3*k)/4+2/3-(71/12) = 0

(3*k)/4+2/3-71/12 = 0

3/4*k-21/4 = 0 // + 21/4

3/4*k = 21/4 // : 3/4

k = 21/4/3/4

k = 7

k = 7

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