(2/3)a+2=1/3(4a+1)

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Solution for (2/3)a+2=1/3(4a+1) equation: 



(2/3)a+2=1/3(4a+1)

We move all terms to the left:

(2/3)a+2-(1/3(4a+1))=0



Domain of the equation: 3)a!=0

a!=0/1

a!=0

a∈R





Domain of the equation: 3(4a+1))!=0

a∈R



We add all the numbers together, and all the variables

(+2/3)a-(1/3(4a+1))+2=0

We multiply parentheses

2a^2-(1/3(4a+1))+2=0

We multiply all the terms by the denominator


2a^2*3(4a+1))-(1+2*3(4a+1))=0

Wy multiply elements

6a^3(4+6a(4=0

We do not support eapression: a^3(4

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