(2/3)a+2=1/3(4a+1)

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Solution for (2/3)a+2=1/3(4a+1) equation:



(2/3)a+2=1/3(4a+1)
We move all terms to the left:
(2/3)a+2-(1/3(4a+1))=0
Domain of the equation: 3)a!=0
a!=0/1
a!=0
a∈R
Domain of the equation: 3(4a+1))!=0
a∈R
We add all the numbers together, and all the variables
(+2/3)a-(1/3(4a+1))+2=0
We multiply parentheses
2a^2-(1/3(4a+1))+2=0
We multiply all the terms by the denominator
2a^2*3(4a+1))-(1+2*3(4a+1))=0
Wy multiply elements
6a^3(4+6a(4=0
We do not support eapression: a^3(4

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