(2/3)m-(4/3)=-8

Solution for (2/3)m-(4/3)=-8 equation:

(2/3)m-(4/3)=-8

We move all terms to the left:

(2/3)m-(4/3)-(-8)=0


Domain of the equation: 3)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+2/3)m-(+4/3)-(-8)=0

We add all the numbers together, and all the variables

(+2/3)m+8-(+4/3)=0

We multiply parentheses

2m^2+8-(+4/3)=0

We get rid of parentheses

2m^2+8-4/3=0

We multiply all the terms by the denominator


2m^2*3-4+8*3=0

We add all the numbers together, and all the variables

2m^2*3+20=0

Wy multiply elements

6m^2+20=0

a = 6; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·6·20
Δ = -480
Delta is less than zero, so there is no solution for the equation